x'=-b-Vλ / 2a
soit : -25 - V665 / 2 x 2
-25 - V665 / 4
x"=-b+Vλ / 2a
soit : -25 - V665 / 2 x 2
-25 - V665 / 2 x 2
Trop la flemme de réduire tout ça ....
pr info le grand V c la racine carrée que j'ai pas trouvé sur internet XD
# Posted on Sunday, 07 October 2007 at 1:40 PM
Edited on Sunday, 07 October 2007 at 2:20 PM
# Posted on Sunday, 07 October 2007 at 1:05 PM
Edited on Wednesday, 10 October 2007 at 5:12 AM
# Posted on Tuesday, 04 September 2007 at 2:48 PM
Edited on Friday, 07 September 2007 at 1:15 PM
# Posted on Thursday, 30 August 2007 at 2:34 PM
Edited on Saturday, 08 September 2007 at 12:48 AM
# Posted on Friday, 10 August 2007 at 1:05 PM